The Hijri date 7/4/7618 corresponds to the Gregorian date of Friday, December 28, 8012. The solar calendar date corresponds to 7 Jadi (Capricorn) 7391, which all occur on one single day, that is Friday. In addition, there is one Julian date, which is 4647745.
| Gregorian date: | Friday, December 28, 8012 |
|---|---|
| Short Gregorian Date: | 12/28/12 |
| Hijri date: | Rabi II 7, 7618 AH |
| Short Hijri Date: | 7/4/7618 |
| Solar date: | 7 Jadi (Capricorn) 7391 |
| Short Solar Date: | 7/4/7391 |
| Day: | Friday |
| Julian date: | 4647745 (Julian) |
According to the calendar, the year 8012 is a leap year as of December 28, 8012.