The Hijri date 11/4/2048 corresponds to the Gregorian date of Friday, November 11, 2608. The solar calendar date corresponds to 20 ‘Aqrab (Scorpio) 1987, which all occur on one single day, that is Friday. In addition, there is one Julian date, which is 2673927.
| Gregorian date: | Friday, November 11, 2608 |
|---|---|
| Short Gregorian Date: | 11/11/08 |
| Hijri date: | Rabi II 11, 2048 AH |
| Short Hijri Date: | 11/4/2048 |
| Solar date: | 20 ‘Aqrab (Scorpio) 1987 |
| Short Solar Date: | 20/2/1987 |
| Day: | Friday |
| Julian date: | 2673927 (Julian) |
According to the calendar, the year 2608 is a leap year as of November 11, 2608.