The Hijri date 25/3/2048 corresponds to the Gregorian date of Wednesday, October 26, 2608. The solar calendar date corresponds to 4 ‘Aqrab (Scorpio) 1987, which all occur on one single day, that is Wednesday. In addition, there is one Julian date, which is 2673911.
| Gregorian date: | Wednesday, October 26, 2608 |
|---|---|
| Short Gregorian Date: | 10/26/08 |
| Hijri date: | Rabi I 25, 2048 AH |
| Short Hijri Date: | 25/3/2048 |
| Solar date: | 4 ‘Aqrab (Scorpio) 1987 |
| Short Solar Date: | 4/2/1987 |
| Day: | Wednesday |
| Julian date: | 2673911 (Julian) |
According to the calendar, the year 2608 is a leap year as of October 26, 2608.