The Hijri date 4/4/2048 corresponds to the Gregorian date of Friday, November 4, 2608. The solar calendar date corresponds to 13 ‘Aqrab (Scorpio) 1987, which all occur on one single day, that is Friday. In addition, there is one Julian date, which is 2673920.
| Gregorian date: | Friday, November 4, 2608 |
|---|---|
| Short Gregorian Date: | 11/4/08 |
| Hijri date: | Rabi II 4, 2048 AH |
| Short Hijri Date: | 4/4/2048 |
| Solar date: | 13 ‘Aqrab (Scorpio) 1987 |
| Short Solar Date: | 13/2/1987 |
| Day: | Friday |
| Julian date: | 2673920 (Julian) |
According to the calendar, the year 2608 is a leap year as of November 4, 2608.