The Hijri date 26/3/2048 corresponds to the Gregorian date of Thursday, October 27, 2608. The solar calendar date corresponds to 5 ‘Aqrab (Scorpio) 1987, which all occur on one single day, that is Thursday. In addition, there is one Julian date, which is 2673912.
| Gregorian date: | Thursday, October 27, 2608 |
|---|---|
| Short Gregorian Date: | 10/27/08 |
| Hijri date: | Rabi I 26, 2048 AH |
| Short Hijri Date: | 26/3/2048 |
| Solar date: | 5 ‘Aqrab (Scorpio) 1987 |
| Short Solar Date: | 5/2/1987 |
| Day: | Thursday |
| Julian date: | 2673912 (Julian) |
According to the calendar, the year 2608 is a leap year as of October 27, 2608.